Will batteries become lighter when they are empty?

I have allowed myself to reformulate the question a little:

“Will batteries become lighter during the discharge process?”

(1) Theoretically no, but PRAKTISCH yes: By dispensing gaseous matter into the environment, through tiny leaks in the battery case, and this can quite cause a measurable mass loss, as by Bernhard Kletzenbauer completely correct Noted.

(2) Theoretically YES. This means: LAW-like: YES.

But PRAKTISCH: NO – and DAMIT is meant: This mass loss is LAW-like, but it is immeasurably small!

Bernhard Kletzenbauer correctly said that the electrons “have returned”.

The material summary composition in the battery – I mean every amount of material of every existing chemical element and (thus) the total amount of electrons – has not changed in the battery!

However, the electron flow or energy transfer has been realized by the fact that the matter, the chemicals (educts) in the battery have received an (electro-)chemical reaction.

Products – Products

These resulting reaction products have exactly less energy, which was transferred to the matter outside the battery.

This energy loss delta(E) in the matter of the battery is a mass loss delta(m) – can also be called mass defect, AEQUIVALENT.

This is calculated from the famous law formula of A.Einstein:

“E = m x c2”

to delta(m) = delta(E) / (c-2)

and is, so to speak, immeasurably small because of the immense size of c-2 (the square of the speed of light).

Unfortunately, I am now too comfortable to give you an example.

But I can use another example for “Products” which I first copied from a physics forum and then recalculated (checked) myself.

When freezing 1 kilogram of water, i.e. the reaction

Water (Educt) – Ice (Product)

corresponds to the energy loss delta(m) – this is nothing but the “lost” crystallization energy, by dispensing heat radiation, a mass defect of 3.7 nanograms.So it’s negligible. Incidentally, the law-like mass-defect does not contradict another legality, which is known as mass preservation: the missing mass is now only where-ANDERST, namely accurate DA, where-the crystallization energy was “lost” – will say: It has been transferred!

EDIT on 20.12.2018 -I submit here the calculation of the mass defect.

solidification heat or crystallization energy,
when freezing water:
delta(E) = 333 500 J = 333 500 kg x m2 / sec2 (see GOOGLE)
for 55.5 mol water = 1 kg water

Equivalent mass defect,
when freezing water:
delta(m) = delta(E) / (c-2) = 333500 ((kg x m2) / (sec-2)) / ((3 x 10×8 m / sec) =
3.7 x 10″-12 kg = 3.7 x 10″-9 grams = 3.7 nanograms
for 55.5 mol water = 1 kg water

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