# How does gravity differ with the distance to the center of the Earth?

This is not easy to explain, because the gravitational quantities are directly related to the electromagnetic quantities and make this somewhat difficult for the inexperienced of four-dimensional ideas.therefore:

You draw a very small circle and therefore a second, a third, etc.until you miss the lust. Now consider how long the circumference of the first circle is and how big the size of the second circle is, then you can also imagine that the third will be even larger.

This steady increase follows a mathematical ratio that determines the radius of your circles.And that radius is getting +1, which ends with the formulation 1/r2.

So the center (your center of the earth) is the point of reference of your contemplation and your observation location then determines the distance to the center, which in turn is a radius.

Now I look at the spatial quantities that each circle needs, where the radius’s scale will be a Planckian length.In the light of our prior knowledge, we know that the gravitational strength towards the center increases, but the quantity ratios decrease. Now people are talking about space curvature and not saying how big the amount is being bent away from our observation area and they don’t tell us where the quantities have gone. They just disappear? And remember, I am not talking about matter in terms of quantities, but about space. Matter is ultimately made of this substance, which now seems to be quantitatively variable.

This could only be explained if each circle is always of the same size, whereby the circle in the circle always a part of the quantity 1/r2 hidden somewhere from our prying eyes.And we already know something like that. It is the electromagnetic, where things concretely present their effects as field lines, but still not on our detectable level. This is the 4th dimension into which the sets curve, where I call this plane a 4D plane and also understand it as an electromagnetic field. I then describe the other layer as a 3D layer, where the other three dimensions curve into the 4D plane, as I would like to illustrate with the following illustration.

The horizontalgray X axis now reflects the spatial density on the 3D plane and the decreasing distances to the center.

The red vertical lines on the Y axis indicate the quantities that have been curved into the 4D plane. The ratio 1/r2 is shown as the red sine arch.

That would be your Earth, but exactly the same would be a photon and if the photon moves through an antenna, then the blue sine curve appears on the oscilloscope.

I think these were enough differences to answer your question.If you want to investigate this further, you should browse into my block.